(18x^4+9x^3+3x^2)/(3x^2+1)

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Solution for (18x^4+9x^3+3x^2)/(3x^2+1) equation: 


D( x )

3*x^2+1 = 0

3*x^2+1 = 0

3*x^2+1 = 0

3*x^2 = -1 // : 3

x^2 = -1/3

x in (-oo:+oo)

(18*x^4+9*x^3+3*x^2)/(3*x^2+1) = 0

18*x^4+9*x^3+3*x^2 = 0

3*x^2*(6*x^2+3*x+1) = 0

6*x^2+3*x+1 = 0

DELTA = 3^2-(1*4*6)

DELTA = -15

DELTA < 0

3*x^2 = 0

(3*x^2)/(3*x^2+1) = 0

3*x^2 = 0 // : 3

x^2 = 0

x = 0

x = 0

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